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Elenco in ordine alfabetico delle domande di 70-229: SQL Server 2000 database design and implementation

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- Barney wrote this stored procedure to manage inserts to his Sales table:
CREATE PROCEDURE InsertSale
@SalesPersonID int,
@ProductID int,
@Quantity int,
@CustomerID int
AS
If @Quantity > 0
Insert Sales (SalesPersonID, ProductID, Quantity, CustomerID)
VALUES (@SalesPersonID, @ProductID, @Quantity, @CustomerID)
else
RAISERROR ('Unable to enter negative or 0 quantity into Sales table.', 16, 1)
GO
What does the RAISERROR statement do?
It provides feedback to the calling application so it can diagnose why the insert failed.

- Barney wrote this stored procedure to manage inserts to his Sales table:
CREATE PROCEDURE InsertSale
@SalesPersonID int,
@ProductID int,
@Quantity int,
@CustomerID int
AS
If @Quantity > 0
Insert Sales (SalesPersonID, ProductID, Quantity, CustomerID)
VALUES (@SalesPersonID, @ProductID, @Quantity, @CustomerID)
else
RAISERROR ('Unable to enter negative or 0 quantity into Sales table.', 16, 1)
GO
If there are no constraints on the table, how can Barney make sure that the value of @SalesPersonID is valid?
Check the table in which SalesPersonID is a Primary Key to ensure that the value is valid.

- Barney wrote this stored procedure to manage inserts to his Sales table:
CREATE PROCEDURE InsertSale
@SalesPersonID int,
@ProductID int,
@Quantity int,
@CustomerID int
AS
If @Quantity > 0
Insert Sales (SalesPersonID, ProductID, Quantity, CustomerID)
VALUES (@SalesPersonID, @ProductID, @Quantity, @CustomerID)
else
RAISERROR ('Unable to enter negative or 0 quantity into Sales table.', 16, 1)
GO
Barney's boss found out about user-defined functions, and wants Barney to rewrite this as a user-defined function. What steps should Barney take to make this happen?
This procedure cannot be rewritten as a function.

- Bill wants to set up full-text searching on the Comments column of his OrderDetail table in the BillCo database. The OrderDetail table has a composite key made up of the OrderID and the ProductID field. Why won't this solution work?
Because there is no single-column unique key for the table.